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-16x^2+15x+4=0
a = -16; b = 15; c = +4;
Δ = b2-4ac
Δ = 152-4·(-16)·4
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{481}}{2*-16}=\frac{-15-\sqrt{481}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{481}}{2*-16}=\frac{-15+\sqrt{481}}{-32} $
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